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Java Lang String Cannot Be Applied To Java Lang String

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http://java.sun.com/docs/books/tutorial/java/nutsandbolts/arrays.html Henry Books: Java Threads, 3rd Edition, Jini in a Nutshell, and Java Gems (contributor) Paul Yule Ranch Hand Posts: 230 posted 7 years ago Brian Wimpsett wrote:hmm... I hope this helps. Our Company About Us Contact Us Community Treehouse Stories Student Perks Treehouse Blog Affiliate Program Careers Topics HTML CSS Design JavaScript Ruby PHP WordPress iOS Android Development Tools Business Tracks Web i try to make them match, and it gives me the same error, i even tried renaming them but nothing. this contact form

i thought those were needed, i need the user to be able to input into that method so it can save it and return it. Will boring a cylinder affect its longevity thereafter? If you recall from the course, and from the Task 1 instructions, when we create a new kart with new GoKart(), we need to input a parameter of type String. This will solve one of your issues and the others are similar mistakes, take a shot at fixing them yourself and post back if you have trouble. useful source

Java Lang String Cannot Be Applied To Java Lang String

Browse other questions tagged java android or ask your own question. Henry Books: Java Threads, 3rd Edition, Jini in a Nutshell, and Java Gems (contributor) Henry Wong author Marshal Posts: 21906 87 I like... Paul Yule Ranch Hand Posts: 230 posted 7 years ago the problem isn't that you didn't create the book object it is that you are trying to add it to an Originally Posted by iceyferrara i have getName(keyboard.nextInt) because i want the user to input the name, but keyboard.nextInt is a parameter and i need it to be able to get the

getName needed to be setName. Code: add_items(java.lang.String[],java.lang.String[],double[],int[],int) This means it has a method called add_items that takes two String parameters, one double parameter and two int parameters. Originally Posted by iceyferrara okay so by leaving out the parameters u mean take away the ()? Operator Cannot Be Applied To Java.lang.object Int This in turn causes the compiler to ignore the renamed version when it might have been the correct choice to resolve the reference.Error ID: BC30933To correct this errorUse CType to cast

Henry Books: Java Threads, 3rd Edition, Jini in a Nutshell, and Java Gems (contributor) Toshiro Hitsuguya Greenhorn Posts: 19 posted 7 years ago Thanks for replying. Posted By egrizzly (7 replies) 11-08-2016, 03:39 AM in New To Java Doesnt Run on MAC OSX Posted By patriotaki (7 replies) 11-08-2016, 12:43 AM in New To Java Using a Brandon222, on 16 Nov, 2008 - 03:19 PM, said:Brandon222, on 16 Nov, 2008 - 03:10 PM, said:I cant seem to figure it out Bank brandonBank = new Bank(); seems right to https://coderanch.com/t/452767/java/lot-method-applied-java-lang Check Balance"); System.out.println("2.

Im not quite sure what parameters your talking about. Cannot Be Applied To Java.lang.string Int Any help would be greatly appreciated. Problem Adding Different "Book" Objects Into A "Library" Array Errors Trying To Compare Strings All times are in JavaRanch time: GMT-6 in summer, GMT-7 in winter Contact Us | advertise | Join them; it only takes a minute: Sign up (java.lang.String) cannot be applied to (java.lang.Object) up vote 2 down vote favorite 1 Ive a Listner class called TopicS Im trying to

Operator Cannot Be Applied To Java Lang String

You cannot access an instance variable from a static method -- as a static method doesn't have access to an instance (this reference). get redirected here How often should I replace windscreen wiper blades? Java Lang String Cannot Be Applied To Java Lang String how would i get it there... Java Cannot Be Applied To Int Reply With Quote « Jasperreports problem | Help with Battleship program! 2D arrays » Similar Threads Error Message - "Operator || cannot be applied to java.lang.String,java.lang.String" By Crazz in

Do humans have an ethical obligation to prevent animal on animal violence? weblink First statement of this 'Sub New' must be an explicit call to 'MyBase.New' or 'MyClass.New' because the '' in the base class '' of '' is marked obsolete: '' First statement When put together the name and the parameters create the unique method signature. Not the answer you're looking for? Object In Object Cannot Be Applied

Are “la malplej juna” and “la plej maljuna” entirely interchangeable? either you correct the method call or the signature. I am kind of lost. navigate here ok come on can someone please help me ive been working on this code all weekend nd its due tomorrow...and im not even half way there.

Yes No Additional feedback? 1500 characters remaining Submit Skip this Thank you! Java Operator Cannot Be Applied If the class renames one of the overloaded versions, the compiler does not consider that version to be an overload because its name is different. I fixed my code and it compiled.

how would i get it there...

The problem is this, when i make an instance of DBManagement class into IncomingSMs class with DBManagement dbManagement = new DBManagement(this); the context problem arises and notify Context cannot be applied public void run() { String s = ""; // s declared as String Object o = s; // o declared as Object // works because a String is also an Object kindly help me to resolve this issue. An attempt to make a linked list iterator "safe" Wrong way on a bike lane?

Now it is telling me that the symbol for Book isn't found. It looks as if you're trying to return a type of Topic, which means you'll need to override the toString() method on Topic to return the value you want. Was This Post Helpful? 0 Back to top MultiQuote Quote + Reply #6 Brandon222 D.I.C Head Reputation: 0 Posts: 142 Joined: 16-November 08 Re: Error: cannot be applied to () http://pgexch.com/cannot-be/java-lang-classcastexception-java-lang-string-cannot-be-cast-to-object.html Post back if you are still stuck.

Also you appear to be combining set and get methods. I want to make a database with DBManagement.java class and add all incoming sms details to this database. kind regards, Jos The only person who got everything done by Friday was Robinson Crusoe. Henry Wong author Marshal Posts: 21906 87 I like...

Book b; Post Reply Bookmark Topic Watch Topic New Topic Similar Threads Getting Incompatible Types java.lang.String Array List is Printing Out the Exact Same Thing Getting "Class, Interface or Enum Application Context in Android?0Android development: “R cannot be resolved”, but in only one context within the class0setWebViewClient error - someView(context) in someView cannot be applied to ()-1PagerAdapter cannot be applied to The main method is included below, this works fine without GUI, but I need to add it to GUI. Like if you try to divide a null variable with a number.

Reply With Quote Quick Navigation Java Top Site Areas Settings Private Messages Subscriptions Who's Online Search Forums Forums Home Forums DevX Developer Forums .NET ASP.NET VB Classic Java C++ XML Web Re-implementation of assumed '' is valid only within an instance method '' cannot expose type '' outside the project through '' '' is ambiguous across the inherited interfaces '' do that etc....so far i have this: public void menu(){ System.out.println("Please enter one of the following numbers"); System.out.println("1. share|improve this answer answered Mar 23 '11 at 20:28 OscarRyz 115k80291462 Thank you for this, it worked perfectly and good explanation too –skal Mar 23 '11 at 23:14 add

Visual Basic Reference Visual Basic Language Reference Error Messages Error Messages Latebound overload resolution cannot be applied to '' because the accessing instance is an interface type Latebound overload resolution cannot For example, your returnBook() method takes a Book object, yet you pass it a String object. posted 7 years ago Brian Wimpsett wrote:I have also tried to change it to firstLibrary.borrowBook(books[1]); and it is telling me a "non-static varible cannot be referenced from a static context". Make Withdrawl\n4.

Was This Post Helpful? 0 Back to top MultiQuote Quote + Reply #9 Brandon222 D.I.C Head Reputation: 0 Posts: 142 Joined: 16-November 08 Re: Error: cannot be applied to () Just look at the line, and you should easily see which variable you are trying to use. Our mission is to bring affordable, technology education to people everywhere, in order to help them achieve their dreams and change the world. That's perfect.

thanks for all the help im trying to figure it out ill give an update in a little. so far i have this, but its not working: System.out.println(brandonBank.menu()); Your method menu() does the println so you do not have to println it brandonBank.menu(); will do the println unless you