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I Cannot Be Cast To Ljava.lang.object

How to reply? I think the element in list is Array ~ –splatter_fadli Dec 10 '13 at 6:40 add a comment| up vote 0 down vote I've faced such an issue and dig tones And then, yes, it is better to make one of the exact size. As Italian citizens, what legal documents are we supposed to carry when traveling to Ireland? Source

Fixed. –Mureinik Apr 23 '15 at 6:03 add a comment| up vote 4 down vote It is returning Object[] Not String[]. Browse other questions tagged java swing object derby or ask your own question. Picking 10 distinct words 'randomly' from List of unique words more hot questions question feed lang-java about us tour help blog chat data legal privacy policy work here advertising info mobile How to prove that authentication system works, and that customer uses the wrong password? http://stackoverflow.com/questions/20486641/ljava-lang-object-cannot-be-cast-to

more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed more hot questions question feed lang-java about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback Technology Life / Arts Culture / Recreation Union and Intersection of two Set in Java - Google... But good explanation actually. –Murat K.

You can then transform the result of the list() method into a more usable form, preferably within it's own method, before passing it on to the rest of your code. When iterating over the ResultList this causes ClassCastExceptions. Let's see a sample code which will throw ClassCastException in Java: Object imObject = new String(); Integer i = (Integer) imObject; Above code will throw Exception in thread "main" java.lang.ClassCastException: java.lang.String Join them; it only takes a minute: Sign up Cannot be cast to [Ljava.lang.Object; up vote 0 down vote favorite 2 I wrote this code to set the a jTable to

Because the method handles any query, I don't know what kind of types are being returned. When I try to run it, it gives following Exception: java.lang.ClassCastException: [Ljava.lang.Object; cannot be cast to com.telemune.demoPojo.CrbtSubMasterDemo
at com.telemune.demoHibernate.QueryTester.getDetails(QueryTester.java:57)
at com.telemune.demoHibernate.QueryTester.main(QueryTester.java:23)
The question is query.list() is returning the asked 1 year ago viewed 20506 times active 1 year ago Upcoming Events 2016 Community Moderator Election ends Nov 22 Linked 0 ClassCastException with inner join (HQL) Related 2java.lang.ClassCastException: java.lang.String cannot http://stackoverflow.com/questions/29372228/ljava-lang-object-cannot-be-cast-to-error They need to be done step by step.

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However, this does not create any immediate problems because inside the Stack class, E is erased to its upper bound, in this case Object. check this link right here now How to Split String in SQL Server and Sybase How to get current date, month, year and day of we... I thought this exception has been forgotten long back. Mar 31 '15 at 15:29 1 I would add "SELECT c" because OP wants/needs to obtain Commerce and there's this "FROM Commerce c" and do an (un)safe cast to List

How to parse or convert String to long in Java - 4... However, the "new" is missing above. –AgilePro Mar 1 '13 at 14:41 I forgot the new Integer part. When whole fields are retrieved from query this wont be a problem splatter_fadli –Ajay Takur Jun 10 at 15:55 add a comment| 3 Answers 3 active oldest votes up vote 15 Would an Agricultural Scythe work as a the Signature Weapon of an Assassin?

I do need it to be an Integer[]. It's also a good idea to refresh your knowledge on type-casting in Java. With Java 7 and above you can use the diamond operator <> like Stack st = new Stack<>(); st.push(ran.nextInt(100)); With earlier versions you specify the generic type like Stack st = have a peek here A problem only occurs when the (incorrect) fact that elements is type E[] is "exposed" to the outside of the class, outside of the scope of the erasure of E, into

Integer number = (Integer) stringObject; java.lang.classcastexception java.lang.string cannot be cast to java.util.date :This error will come when you cast String to Date in Java, since both are not related to each GO OUT AND VOTE Why is looping over find's output bad practice? share|improve this answer edited Mar 31 '15 at 17:09 durron597 23.3k105194 answered Mar 31 '15 at 15:34 alias_boubou 1666 Hi, welcome to Stack Overflow!

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Post Reply Bookmark Topic Watch Topic New Topic programming forums Java Java JSRs Mobile Certification Databases Caching Books Engineering Languages Frameworks Products This Site Careers Other all forums Forum: Object Relational This is the preferable method if you need to select more than just the Commerce object. An attempt to make a linked list iterator "safe" Complement of CFL is Recursive Wrong way on a bike lane? Join them; it only takes a minute: Sign up ClassCastException: java.lang.Object cannot be cast to java.lang.Integer up vote 5 down vote favorite 2 The root of my problem is that I

How to find duplicate records in a table on databa... How Many Acute Angles Why is (a % 256) different than (a & 0xFF)? Wrong way on a bike lane? I believe that your query should return a List, not List.

Consider Stack st = new Stack<>(); instead. The declaration of E is protected E[] elements = null; This is how I am trying to call Random ran = new Random(); Stack st = new Stack(); st.push(ran.nextInt(100)); Update Guys, Then just use Stack. I am new to Hibernate, sorry if its a silly question.

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